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GMRES

The most important use of the Arnoldi iteration is to solve the square linear system Ax=b\mathbf{A}\mathbf{x}=\mathbf{b}.

In Demo 8.4.1, we attempted to replace the linear system Ax=b\mathbf{A}\mathbf{x}=\mathbf{b} by the lower-dimensional approximation

minxKmAxb=minzCmAKmzb,\min_{\mathbf{x}\in \mathcal{K}_m} \| \mathbf{A}\mathbf{x}-\mathbf{b} \| = \min_{\mathbf{z}\in\mathbb{C}^m} \| \mathbf{A}\mathbf{K}_m\mathbf{z}-\mathbf{b} \|,

where Km\mathbf{K}_m is the Krylov matrix generated using A\mathbf{A} and the seed vector b\mathbf{b}. This method was unstable due to the poor conditioning of Km\mathbf{K}_m, which is a numerically poor basis for Km\mathcal{K}_m.

The Arnoldi algorithm yields an orthonormal basis of the same space and fixes the stability problem. Set x=Qmz\mathbf{x}=\mathbf{Q}_m\mathbf{z} and obtain

minzCmAQmzb.\min_{\mathbf{z}\in\mathbb{C}^m}\, \bigl\| \mathbf{A} \mathbf{Q}_m \mathbf{z}-\mathbf{b} \bigr\|.

From the fundamental Arnoldi identity (8.4.9), this is equivalent to

minzCmQm+1Hmzb.\min_{\mathbf{z}\in\mathbb{C}^m}\, \bigl\| \mathbf{Q}_{m+1} \mathbf{H}_m\mathbf{z}-\mathbf{b} \bigr\|.

Note that q1\mathbf{q}_1 is a unit multiple of b\mathbf{b}, so b=bQm+1e1\mathbf{b} = \|\mathbf{b}\| \mathbf{Q}_{m+1}\mathbf{e}_1. Thus (8.5.3) becomes

minzCmQm+1(Hmzbe1).\min_{\mathbf{z}\in\mathbb{C}^m}\, \bigl\| \mathbf{Q}_{m+1} (\mathbf{H}_m\mathbf{z}-\|\mathbf{b}\|\mathbf{e}_1) \bigr\|.

The least-squares problems (8.5.2), (8.5.3), and (8.5.4) are all n×mn\times m. But observe that for any wCm+1\mathbf{w}\in\mathbb{C}^{m+1},

Qm+1w2=wQm+1Qm+1w=ww=w2. \|\mathbf{Q}_{m+1}\mathbf{w}\|^2 = \mathbf{w}^*\mathbf{Q}_{m+1}^*\mathbf{Q}_{m+1}\mathbf{w} = \mathbf{w}^*\mathbf{w} = \|\mathbf{w}\|^2.

The first norm in that equation is on Cn\mathbb{C}^n, while the last is on the much smaller space Cm+1\mathbb{C}^{m+1}. Hence the least-squares problem (8.5.4) is equivalent to

minzCmHmzbe1, \min_{\mathbf{z}\in\mathbb{C}^m}\, \bigl\| \mathbf{H}_m\mathbf{z}-\|\mathbf{b}\|\,\mathbf{e}_1 \bigr\|,

which is of size (m+1)×m(m+1)\times m. We call the solution of this minimization zm\mathbf{z}_m, and then xm=Qmzm\mathbf{x}_m=\mathbf{Q}_m \mathbf{z}_m is the mmth approximation to the solution of Ax=b\mathbf{A}\mathbf{x}=\mathbf{b}.

GMRES[1] uses the Arnoldi iteration to minimize the residual bAx\mathbf{b} - \mathbf{A}\mathbf{x} over successive Krylov subspaces. In exact arithmetic, GMRES should get the exact solution when m=nm=n, but the goal is to reduce the residual enough to stop at some mnm \ll n.[2]

Compare the graph in Demo 8.5.1 to the one in Demo 8.4.1. Both start with the same linear convergence, but only the version using Arnoldi avoids the instability created by the poor Krylov basis.

A basic implementation of GMRES is given in Function 8.5.2.

8.5.1Convergence and restarting

Thanks to Theorem 8.4.1, minimization of bAx\|\mathbf{b}-\mathbf{A}\mathbf{x}\| over Km+1\mathcal{K}_{m+1} includes minimization over Km\mathcal{K}_m. Hence the norm of the residual rm=bAxm\mathbf{r}_m = \mathbf{b} - \mathbf{A}\mathbf{x}_m (being the minimized quantity) cannot increase as the iteration unfolds.

Unfortunately, making other conclusive statements about the convergence of GMRES is neither easy nor simple. Demo 8.5.1 shows the cleanest behavior: essentially linear convergence down to the range of machine epsilon. But it is possible for the convergence to go through phases of sublinear and superlinear convergence as well. There is a strong dependence on the eigenvalues of the matrix, a fact we state with more precision and detail in the next section.

One of the practical challenges in GMRES is that as the dimension of the Krylov subspace grows, the number of new entries to be found in Hm\mathbf{H}_m and the total number of columns in Q\mathbf{Q} also grow. Thus both the work and the storage requirements are quadratic in mm, which can become intolerable in some applications. For this reason, GMRES is often used with restarting.

Suppose x^\hat{\mathbf{x}} is an approximate solution of Ax=b\mathbf{A}\mathbf{x}=\mathbf{b}. Then if we set x=u+x^\mathbf{x}=\mathbf{u}+\hat{\mathbf{x}}, we have A(u+x^)=b\mathbf{A}(\mathbf{u}+\hat{\mathbf{x}}) = \mathbf{b}, or Au=bAx^\mathbf{A}\mathbf{u} = \mathbf{b} - \mathbf{A}\hat{\mathbf{x}}. The conclusion is that if we get an approximate solution and compute its residual r=bAx^\mathbf{r}=\mathbf{b} - \mathbf{A}\hat{\mathbf{x}}, then we need only to solve Au=r\mathbf{A}\mathbf{u} = \mathbf{r} in order to get a correction to x^\hat{\mathbf{x}}.[3]

Restarting guarantees a fixed upper bound on the per-iteration cost of GMRES. However, this benefit comes at a price. Even though restarting preserves progress made in previous iterations, the Krylov space information is discarded and the residual minimization process starts again over low-dimensional spaces. That can significantly retard or even stagnate the convergence.

Restarting creates a tradeoff between the number of iterations and the speed per iteration. It’s essentially impossible in general to predict the ideal restart location in any given problem, so one goes by experience and hopes for the best.

There are other ways to avoid the growth in computational effort as the GMRES/Arnoldi iteration proceeds. Three of the more popular variations are abbreviated CGS, BiCGSTAB, and QMR. We do not describe them in this book.

8.5.2Exercises

  1. ✍ (See also Exercise 8.4.1.) Consider the linear system with

    A=[0100001000011000],b=e1.\mathbf{A}=\displaystyle \begin{bmatrix} 0 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \\ 1 & 0 & 0 & 0 \end{bmatrix}, \qquad \mathbf{b}=\mathbf{e}_1.

    (a) Find the exact solution by inspection.

    (b) Find the GMRES approximate solutions xm\mathbf{x}_m for m=1,2,3,4m=1,2,3,4.

  2. ✍ (Continuation of Exercise 8.4.3.) Show that if xmKm\mathbf{x}_m\in\mathcal{K}_m, then the residual bAxm\mathbf{b}-\mathbf{A}\mathbf{x}_m is equal to q(A)bq(\mathbf{A})\mathbf{b}, where qq is a polynomial of degree at most mm and q(0)=1q(0)=1. (This fact is a key one for many convergence results.)

  3. ✍ Explain why GMRES, in exact arithmetic, converges to the true solution in nn iterations for an n×nn\times n matrix if rank(Kn)=n\operatorname{rank}(\mathbf{K}_n)=n. (Hint: Consider how the algorithm is defined from first principles.)

  4. ⌨ Let A\mathbf{A} be the n×nn\times n tridiagonal matrix

    [4114114114]\begin{bmatrix} -4 & 1 & & & \\ 1 & -4 & 1 & & \\ & \ddots & \ddots & \ddots & \\ & & 1 & -4 & 1 \\ & & & 1 & -4 \end{bmatrix}

    and let the nn-vector b\mathbf{b} have elements bi=i/nb_i=i/n. For n=8,16,32,64n=8,16,32,64, run Function 8.5.2 for m=n/2m=n/2 iterations. On one semi-log graph, plot rk/b\|\mathbf{r}_k\|/\|\mathbf{b}\| for all the cases. How does the convergence rate of GMRES seem to depend on nn?

  1. ⌨ In this exercise you will see the strong effect the eigenvalues of the matrix may have on GMRES convergence. Let

    B=[12100],\mathbf{B}= \begin{bmatrix} 1 & & & \\ & 2 & & \\ & & \ddots & \\ & & & 100 \end{bmatrix},

    let I\mathbf{I} be a 100×100100\times 100 identity, and let Z\mathbf{Z} be a 100×100100\times 100 matrix of zeros. Also let b\mathbf{b} be a 200×1200\times 1 vector of ones. You will use GMRES with restarts, as in Demo 8.5.2 (i.e., not the book’s version of gmres).

    (a) Let A=[BIZB].\mathbf{A} = \begin{bmatrix} \mathbf{B} & \mathbf{I} \\ \mathbf{Z} & \mathbf{B} \end{bmatrix}. What are its eigenvalues (no computer required here)? Apply gmres with tolerance 10-10 for 100 iterations without restarts, and plot the residual convergence.

    (b) Repeat part (a) with restarts every 20 iterations.

    (c) Now let A=[BIZB].\mathbf{A} = \begin{bmatrix} \mathbf{B} & \mathbf{I} \\ \mathbf{Z} & -\mathbf{B} \end{bmatrix}. What are its eigenvalues? Repeat part (a). Which matrix is more difficult for GMRES? (Note: Even though this matrix is triangular, GMRES has no way of exploiting that fact.)

  2. ⌨ (Continuation of Exercise 8.3.5.) We again consider the n2×n2n^2\times n^2 sparse matrix defined by FNC.poisson(n). The solution of Ax=b\mathbf{A}\mathbf{x}=\mathbf{b} may be interpreted as the deflection of a lumped membrane in response to a load represented by b\mathbf{b}.

    (a) For n=10,15,20,25n=10,15,20,25, let b\mathbf{b} be the vector of n2n^2 ones and apply Function 8.5.2 for 50 iterations. On one semi-log graph, plot the four convergence curves rm/b\|\mathbf{r}_m\|/\|\mathbf{b}\|.

    (b) For the case n=25n=25 make a surface plot of x after reshaping it to a 25×25 matrix. It should look physically plausible (though upside-down for a weighted membrane).

Footnotes
  1. GMRES stands for Generalized Minimum RESidual. We will encounter its precursor MINRES in MINRES and conjugate gradients.

  2. This statement is not strictly correct for rare special cases of breakdown where the rank of Kn\mathcal{K}_n is less than nn. In that situation, some additional steps must be taken that we do not discuss here.

  3. The new problem needs to be solved for accuracy relative to b\|\mathbf{b}\|, not relative to r\|\mathbf{r}\|.